Work Done by a Horizontal Force on a Stubborn Pig
How much work is done by a constant horizontal force with magnitude 21.5 N and direction 37.0∘ counterclockwise from the +x-axis on a pig?
Given data:- Force magnitude: 21.5 N- Force direction: 37.0 degrees counterclockwise from the +x-axis
Calculating the Work Done by the Force on the Pig
The work done by the force on the pig can be calculated using the formula:
Work = Force * Displacement * cos(θ)
Where:- Force = 21.5 N- Displacement = Not provided in the question- θ (theta) = 37.0 degrees counterclockwise from the +x-axis
When calculating work done by a force, we use the formula:
Work = Force * Displacement * cos(θ)
Where:- Force = 21.5 N- Displacement = Not provided in the question- θ (theta) = 37.0 degrees counterclockwise from the +x-axis
To find the work done, we need to find the displacement. Since the magnitude of displacement is not given, we can break it into its x and y components. The x-component of the force can be calculated as:
Fx = 21.5 N * cos(37°)
And the y-component of the force can be calculated as:
Fy = 21.5 N * sin(37°)
Now, we need more information about the displacement, either its magnitude or its x and y components, to calculate the work done. Without this information, we cannot proceed with the calculation.