What Fraction of Ice is Submerged When it Floats in Freshwater?

What fraction of ice is submerged when it floats in freshwater, given the density of water at 0°C is very close to 1000kg/m3? take the density of ice to be 0.917 g/cm3.

The fraction of ice is submerged when it floats in freshwater with a density of water at 0°C is 0.917 g. By using the Archimedes principle, the buoyancy force of an object is equal to the weight of the fluid it displaces. The buoyancy force is the force that acted upwards. Fb = W(fluids) Fb is the buoyancy force and W is the weight of fluids. Fraction submerged = ρ(ice)/ρ(fluid), where ρ(ice) is the density of ice and ρ(fluid) is the density of fluids. From the given, ρ(ice) = 917 g/cm³, ρ(fluid) = 1000 g/cm³. Fraction submerged = 917/1000 = 0.917 g/cm³. Thus, the fraction of ice submerged is 0.917 g/m. Final answer: Using Archimedes' Principle, the fraction of ice submerged when it floats in freshwater is determined by the ratio of the density of ice (917 kg/m³) to that of freshwater (1000 kg/m³), resulting in 91.7% of the ice being submerged.

Explanation:

The question is related to Archimedes' Principle, which explains how the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. To find out what fraction of ice is submerged when it floats in freshwater, you can use the densities of ice and water. Given that the density of ice is 0.917 g/cm³ (which is equivalent to 917 kg/m³) and the density of freshwater at 0°C is 1000 kg/m³, to find the fraction of ice submerged (Vsub/Vice) you can apply the ratio of the densities: Vsub/Vice = ρice/ρwater = 917 kg/m³ / 1000 kg/m³ = 0.917. So, 91.7% of the ice is submerged when it floats in freshwater. This means that 91.7% of the volume of the ice is below the water surface, illustrating the buoyant effect of water on ice.
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