The Magnificent Eagle and Its Impressive Power

How much work did the eagle do on the fish? The answer to your question is D. 4500 J.

Work can be calculated using the formula W = Fd, where W is work, F is force, and d is distance. In this scenario, the eagle used a force of 90 N to carry the fish up to a height of 50 m.

Given:

Force (F) = 90 N

Distance (d) = 50 m

Work (W) = ?

Using the formula and substituting the values:

Work = Force x Distance

Work = 90 N x 50 m

Work = 4500 Nm

Therefore, the eagle did a total of 4500 Joules of work on the fish to carry it up into the sky. That's quite an impressive feat of strength from our feathered friend!

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