Reflection on Induced emf in a Wire Moving Across a Magnetic Field

What is the induced emf in the wire?

A. 0.27 volts

B. 1.5 volts

C. 0.65 volts

D. 27 volts

Answer:

The induced emf in the wire is 0.27 volts.

Induced electromotive force (emf) in a wire moving across a magnetic field is a fascinating concept in physics. In this scenario, the length of the wire is 0.65 meters and it is moving perpendicularly across a magnetic field with a velocity of 15 meters/second. The strength of the magnetic field is 2.8 × 10^-2 newtons/ampere·meter.

The formula to calculate induced emf is E = B * L * v, where E is the induced emf, B is the magnetic field strength, L is the length of the wire, and v is the velocity of the wire.

Plugging in the given values into the formula, we get:

E = (2.8 × 10^-2 N/A·m) * (0.65 m) * (15 m/s)

E = 0.27 volts

Therefore, the induced emf in the wire is 0.27 volts. This phenomenon showcases the intricate relationship between magnetic fields, movement, and electromotive force.

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