Let's Calculate Some Physics Fun!

What is the acceleration of an object that starts from rest and reaches a velocity of 6m/s after traveling 9m?

a) 1m/s^2

b) 2m/s^2

c) 3m/s^2

d) 4m/s^2

Answer:

The correct answer is b) 2m/s^2

To solve this question, we can use the kinematic equation:

vf^2 = vi^2 + 2ad

Where:

vf = final velocity (6m/s)

vi = initial velocity (0, as the object starts from rest)

d = distance traveled (9m)

a = acceleration (what we need to find)

Now, we can plug in the values and solve for acceleration:

6^2 = 0^2 + 2 * a * 9

36 = 18a

a = 36 / 18 = 2m/s^2

Therefore, the acceleration of the object is 2m/s^2 as it travels from rest to a velocity of 6m/s after covering a distance of 9m. Physics can be fun, right?