How high is the cliff above the water?
A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
To solve this problem, we can use the equation of motion for an object in free fall:
s = ut + (1/2)at^2
Where:
- s is the total distance traveled (in meters)
- u is the initial velocity (in meters per second)
- t is the time taken (in seconds)
- a is the acceleration due to gravity (approximately 9.8 m/s^2)
Given that the person's mass is 55 kg and the time taken to hit the water is 5.8 seconds, we first calculate the initial velocity using the equation:
u = gt
u = 9.8 * 5.8 = 56.84 m/s
Now, we can find the height of the cliff above the water by rearranging the equation of motion:
s = ut + (1/2)at^2
s = 56.84 * 5.8 + (1/2) * 9.8 * (5.8)^2 = 328.024 meters
Therefore, the cliff is 328.024 meters above the water.
A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
The cliff is 328.024 meters above the water.