Displacement Calculation of a Plane Traveling from Pittsburg to Orlando to Charlotte

What is the plane's displacement in meters?

The displacement of the plane is equal to 809 Km.

Explanation:

Displacement can be defined as the shortest distance between two points on the path. It is a vector parameter because it has both direction and magnitude. Displacement may be positive, negative, or zero and can change with time.

Consider that A is Pittsburg, B is Charlotte, and C is Orlando. Given, the distance between Pittsburg to Orlando, AC = 1562 Km and the distance from Orlando to Charlotte, BC = 753 Km. Displacement is the distance between the starting point (Pittsburg) and the ending point (Charlotte).

Therefore, the displacement of the plane, AB = AC - BC = 1562 - 753 = 809 Km.

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