Camel's Journey to Oasis B

Imagining a Cartesian coordinate plane, let's place oasis A at point (0,0) and oasis B at point (25,0).

The camel first walks 24 km in a direction 20° south of east. This can be broken down into x and y components:

x = 24 * cos(20°) ≈ 22.55 km

y = 24 * sin(20°) ≈ -8.21 km

After this leg of the journey, the camel's position is at approximately (22.55, -8.21).

Next, the camel walks 7.0 km due north, which increases its y-coordinate:

new y-coordinate = -8.21 + 7 = -1.21 km

Now, to find the distance from the camel's current position to oasis B:

D = √((25 - 22.55)² + (-1.21 - 0)²) = 2.73 km

Therefore, the camel is approximately 2.73 km away from oasis B after its journey.