Calculating the Initial Velocity and Height of a Cliff Diver

Questions:

A. What was the cliff diver's initial velocity?

B. What is the height of the cliff?

Answers:

Final answer: The cliff diver's initial horizontally velocity was approximately 1.61 meters per second, and the height of the cliff from which the diver jumped was approximately 25.94 meters.

Explanation:

To determine the initial velocity of the cliff diver:

Since the diver jumps horizontally, we can calculate the initial velocity using the formula:

Initial velocity = distance / time = 3.7 meters / 2.3 seconds ≈ 1.61 m/s

To calculate the height of the cliff:

We can use the free-fall motion equation for vertical displacement:

Height of the cliff = 0.5 * g * t^2

Height = 0.5 * 9.81 m/s^2 * (2.3 s)^2 ≈ 25.94 meters

Therefore, the cliff diver's initial velocity was approximately 1.61 m/s, and the height of the cliff was approximately 25.94 meters.