Calculating Power Dissipation in a Series Circuit

What is the calculation for power dissipated by lamps in a series circuit?

How do we calculate the power dissipated by each lamp in a series circuit with a 10V battery?

Calculation for Power Dissipation in a Series Circuit

In a series circuit with two lamps having resistances of 20 ohm and 30 ohm connected to a 10V battery, the current in the circuit can be calculated using the formula:

I = V/R (series circuit)

Resistance of the circuit, R = R₁ + R₂

Using the given values:

I = 10/(20 + 30)

I = 0.1667A

Now, we can calculate the power dissipated by each lamp using Ohm's Law:

For the 20 ohm lamp:

P = I²R = (0.1667)² × 20

P = 0.5556 Watts

For the 30 ohm lamp:

P = I²R = (0.1667)² × 30

P = 0.8333 Watts

When two lamps with resistances of 20 ohm and 30 ohm are connected in series with a 10V battery, the power dissipated by each lamp can be calculated by first finding the current in the circuit using Ohm's Law. The current value is then used to determine the power dissipated by each lamp based on their respective resistances.

The power dissipated by the 20 ohm lamp is 0.5556 Watts, while the power dissipated by the 30 ohm lamp is 0.8333 Watts. This calculation helps in understanding how electrical energy is distributed in a series circuit and how the resistances of individual components affect power dissipation.