Calculating Kinetic Energy of a Person in an Elevator
Question:
If an elevator is moving at a speed of 5 m/s and the person in it is 82 kg, what is the person’s kinetic energy?
Answer:
The person's kinetic energy is 1025J.
Explanation:
Kinetic Energy Formula:
KE = 1/2 * m * v^2
Plugging in the given values:
KE = 1/2 * 82 * 5^2
KE = 1/2 * 82 * 25
KE = 41 * 25
KE = 1025J
Therefore, the kinetic energy of the person in the elevator moving at a speed of 5 m/s is 1025J.