Calculating Force Between Jumper Cables
Explaining the Calculation:
Jumper Cable Setup: Jumper cables consist of a matched pair of wires, typically red and black, joined together along their length. In this scenario, the two wires are separated by 1.2 cm along their 3.7 m length.
Current in the Cables: Each wire carries a current of 150 A, flowing in opposite directions.
Formula Used: The force between the two wires can be calculated using the formula:
F = (μâ * iâ * iâ * l) / (2 * Ï * r)
Where:
- F is the force between the wires
- μâ is the vacuum permeability constant (4Ï x 10^-7 H/m)
- iâ and iâ are the currents in the cables (150 A each)
- l is the length of the cables (3.7 m)
- r is the radius of the cables (1.2 cm = 0.012 m)
Plugging in Values:
μâ = 4Ï x 10^-7
iâ = 150 A
iâ = 150 A
l = 3.7 m
r = 1.2 cm = 0.012 m
Calculating the Force:
F = (4Ï x 10^-7 * 150 * 150 * 3.7) / (2 * Ï * 0.012)
F = 1.3875 N
Therefore, the force between the two wires of the jumper cables is 1.3875 Newtons.