A Helicopter's Ascension and a Stone's Descent
How long does it take for a stone to reach the ground when dropped from a helicopter that is ascending with a velocity of 19.6m/s at a distance of 156.8m above the ground?
The time takes by the stone takes to reach the ground is 2 sec. Velocity is the directional pace of an item in motion as an indication of its rate of exchange in the role as determined from a selected frame of reference and as measured by way of a selected standard of time.
Calculating the Time for the Stone to Reach the Ground
Using the equation S = ut + 1/2 at², where S is the distance the stone falls (156.8m), u is the initial velocity (0m/s for the stone), a is the acceleration due to gravity (9.8m/s²), and t is the time taken: 156.8 = 0t + 1/2 × 9.8t² 4.9t² + 0 - 156.8 = 0 t = 2 sec Therefore, it takes 2 seconds for the stone to reach the ground after being dropped from the ascending helicopter. Average velocity is defined as the trade in position or displacement (∆x) divided by the time durations (∆t) wherein the displacement takes place. The common velocity can be effective or negative depending upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1). Average velocity is calculated by means of dividing your displacement (a vector pointing out of your initial role in your final position) through the entire time; the average pace is calculated by way of dividing the overall distance you traveled by means of the total time.