A Flowerpot Falling from a Balcony: Calculating Time to Hit Ground

A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground

The distance a falling object falls in some amount of time is D = 1/2 a T². If this flowerpot falls off a balcony on Earth, then 'a' is the acceleration of gravity on Earth, and we can write:

85 m = 1/2 (9.8 m/s²) T²

Divide each side by 4.9 m/s²:

85/4.9 s² = T²

Square root each side:

T = √(85/4.9) seconds

T = 4.165 seconds

It will take 4.12 seconds for the flowerpot to fall to the ground.

From the question given above, the following data were obtained:

Height (h) = 85 m

Time (t) = ?

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the flowerpot to fall to the ground can be obtained as follows:

H = ½gt²

85 = ½ × 10 × t²

85 = 5 × t²

Divide both sides by 5:

t² = 17

Take the square root of both sides: t = √17

t = 4.12 s

Therefore, it will take 4.12 seconds for the flowerpot to fall to the ground.

How long does it take for the flowerpot to fall to the ground?

The flowerpot takes 4.12 seconds to hit the ground when falling from a balcony 85m above the street.