A Ball is Kicked at an Angle of 60° with an Initial Velocity of 10 m/s

Kinematics of a Projectile

A ball is kicked from level ground at an angle 60° with initial velocity 10 m/s. The projectile motion of the ball can be analyzed using the laws of physics. One important parameter to consider is the range, which is the horizontal distance traveled by the projectile. In this case, we need to determine how far the ball travels.

Calculation of Distance Traveled

The distance the ball travels, in meters, is: Answer: The ball travels a distance of 8.84 m Explanation: Range is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again. The formula to calculate the range is: R = (U²sin2∅)/g ............... Equation 1 Where: R = range U = initial velocity ∅ = angle of projection g = acceleration due to gravity Given: U = 10 m/s ∅ = 60° Constant: g = 9.8 m/s² Substituting these values into equation 1, we get: R = [10²×sin(2×60)]/9.8 R = (100sin120)/9.8 R = 100×0.8660/9.8 R = 86.60/9.8 R = 8.84 m Therefore, the ball travels a distance of 8.84 meters in its projectile motion.

What is the definition of range in projectile motion?

In projectile motion, range is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again.

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