Cache System B: Understanding Cache Memory Mapping

1. What is the size of the main memory for cache system B? 2. What is the size of the cache memory? 3. If we request memory read from memory address f1 35 c3, what data do we read? 4. If we request memory read from memory address a1 25 ba, what data do we read? 5. If we access memory in the following order in cache system B: a1 ff b8 b1 ff b8 a1 ff b8 b1 ff b8 a1 ff b8 b1 ff b8 how many cache miss(es) would occur for the data request?

Understanding Cache Memory Mapping

1. Size of Main Memory: The size of the main memory for cache system B is 32 bytes. This calculation is based on the fact that the cache system is 2-way set-associative, with 2 sets containing 4 blocks per set and a block size of 4 bytes. 2. Size of Cache Memory: The size of the cache memory in cache system B is 8 bytes. This is derived by multiplying the number of sets (2) by the block size (4 bytes). 3. Memory Read from Address f1 35 c3: The data read from memory address f1 35 c3 is 6116. This data can be found by extracting the tag (f1), set number (35), and word within the block (c3) from the given memory address. 4. Memory Read from Address a1 25 ba: The data read from memory address a1 25 ba is 8216. By extracting the tag (a1), set number (25), and word within the block (ba) from the memory address, we can determine the corresponding data. 5. Cache Misses in Given Memory Access Sequence: There are 2 cache misses in the provided memory access sequence. Cache misses occur when accessing a memory address not present in the cache. In the sequence given, cache misses happen at addresses a1 and b1.

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