What Percentage of Heat Released by Rock was Absorbed by Water?
How do I determine the percentage of heat absorbed by the water?
Determining Heat Released by the Rock:
- Mass of rock (M) = 40 g
- Initial temperature of rock (T₁) = 100 °C
- Final temperature of rock (T₂) = 40 °C
- Change in temperature of rock (ΔT) = 40 - 100 = -60 °C
- Specific heat capacity of rock (C) = 0.84 J/gºC
Q = MCΔT
Q = 40 × 0.84 × -60
Q = -2016 J
Determining Heat Absorbed by the Water:
Next, we shall determine the heat absorbed by the water using the data provided:- Volume of water (V) = 45 mL
- Mass of water (M) = 45 g
- Initial temperature of water (T₁) = 30 °C
- Final temperature of water (T₂) = 40 °C
- Change in temperature of water (ΔT) = 40 - 30 = 10 °C
- Specific heat capacity of water (C) = 4.186 J/gºC
Q = MCΔT
Q = 45 × 4.186 × 10
Q = 1883.7 J
Calculating Percentage of Heat Absorbed by Water:
Finally, let's determine the percentage of heat absorbed by the water using the calculated values:- Heat released by rock = 2016 J
- Heat absorbed by water = 1883.7 J
Percentage of heat absorbed = (Heat absorbed by water / Heat released) × 100
Percentage of heat absorbed = (1883.7 / 2016) × 100
Percentage of heat absorbed = 93.4%