Optimistic Outlook on Concentration Calculations

How does evaporation affect the concentration of a solution?

Upon heating, 253 mL of water was evaporated from 617 mL of 0.310 m C6H12O6(aq). What is the resulting concentration of this solution?

Answer:

The concentration of the glucose solution after 253 mL of water evaporates from an initial 617 mL solution is 0.5255 mol/L.

When water is evaporated from a solution, the concentration of the solute becomes more concentrated in the remaining solution. In this scenario, where 253 mL of water is evaporated from a 617 mL solution of 0.310 m C6H12O6(aq), the new concentration of the solution is calculated as follows:

Initially, the solution had a concentration of 0.310 mol/L. The volume of the solution was 617 mL, but after evaporation, only 364 mL of the solution remained. The number of moles of glucose in the solution remains constant, so the initial moles of glucose can be calculated as (0.310 mol/L) x (0.617 L) = 0.19127 mol.

After the evaporation, the moles of glucose are now in a reduced volume of water. The new concentration of the solution can be calculated as (0.19127 mol) / (0.364 L) = 0.5255 mol/L. Therefore, the concentration of the glucose solution after the evaporation is 0.5255 mol/L.

It is important to understand how evaporation impacts the concentration of a solution, as it can lead to changes in the properties of the solution and its effectiveness in various applications. By calculating the new concentration, we can determine the strength and composition of the solution accurately.

By staying optimistic and proactive in understanding and applying concentration calculations, we can enhance our knowledge and skills in chemistry, leading to successful experiments and outcomes.