How to Calculate Volume of Potassium Iodide Solution?
What is the volume of a 0.998 mol/L potassium iodide solution containing 200.g of KI?
Calculate the volume in liters of a 0.998 mol/L potassium iodide solution that contains 200.g of potassium iodide (KI). Round your answer to 3 significant digits.
Answer:
The volume of the potassium iodide solution is 0.382 L.
To calculate the volume of a potassium iodide solution, we need to follow these steps:
- Calculate the molar mass of potassium iodide (KI):
Molar Mass of KI = Atomic Mass of K + Atomic Mass of Iodine = 39.0983 g/mol + 126.90447 g/mol = 166.00277 g/mol - Determine the number of moles of potassium iodide in the solution:
Number of Moles of KI = Mass of KI / Molar Mass of KI = 200 g / 166.00277 g/mol = 1.2019 mol - Calculate the volume of the solution:
Volume of Solution = Number of Moles of KI / Concentration of Solution = 1.2019 mol / 0.998 mol/L = 1.204 L
Therefore, the volume of the potassium iodide solution containing 200.g of KI is 0.382 liters, rounded to 3 significant digits.