How many hydrogen atoms are in 709 grams of water?
What is the calculation to determine the number of hydrogen atoms in 709 grams of water?
The number of hydrogen atoms in 709 grams of water can be calculated by considering the molecular formula of water, which is H2O. In one molecule of water, there are two hydrogen atoms and one oxygen atom. To calculate the number of hydrogen atoms in 709 grams of water, we need to convert the mass of water to the number of hydrogen atoms based on the molecular weight. First, we need to determine the molecular weight of one hydrogen atom and one oxygen atom. The atomic weight of hydrogen is approximately 1 gram/mol, while the atomic weight of oxygen is around 16 grams/mol. By adding the atomic weights of two hydrogen atoms and one oxygen atom, we get: 2(1) + 16 = 18 grams/mol This means that one mole of water (H2O) weighs 18 grams. Therefore, one mole of water contains 2 moles of hydrogen atoms (2H) and 1 mole of oxygen atom (O). To find the number of hydrogen atoms in 709 grams of water, we can set up a proportion: 1 mole (H2O) = 18 grams (H2O) 2 moles (H) = 2 grams (H) x atoms (H) = 709 grams (H2O) By using the formula weight = mass/mol, we can determine the number of hydrogen atoms in 709 grams of water: 709 grams / 18 grams/mol = 39 moles (H2O) 39 moles (H2) = 39 x 6.02 x 10^23 atoms (H) = 2.35 x 10^25 atoms (H) Therefore, there are 2.35 x 10^25 hydrogen atoms in 709 grams of water. In simpler terms, there are approximately 26 hydrogen atoms present in 709 grams of water.