How many grams of diethyl ether from ethyl alcohol?
What are moles?
A mole is defined as 6.02214076 × 10^23 of some chemical unit, be it atoms, molecules, ions, or others.
How many grams of diethyl ether would you obtain from 41.8 g of ethyl alcohol if the percent yield of the reaction is 76.6%?
25.54 g of diethyl ether would you obtain from 41.8 g of ethyl alcohol if the percent yield of the reaction is 76.6%.
Answer:
Based on the given data, you would obtain 25.54 grams of diethyl ether from 41.8 grams of ethyl alcohol with a percent yield of 76.6%.
In this chemical reaction, the preparation of diethyl ether from ethyl alcohol involves calculating the moles of each substance and applying the concept of percent yield.
To determine the grams of diethyl ether obtained from 41.8 grams of ethyl alcohol, you first calculate the moles of ethyl alcohol using its molar mass. Then, based on the balanced chemical equation, you find the theoretical moles of diethyl ether produced. Considering the percent yield, you calculate the actual moles of diethyl ether formed and finally convert it to grams.
In this case, the calculated amount is 25.54 grams, which is the final yield of diethyl ether from the given amount of ethyl alcohol. Understanding moles and percent yield is crucial in predicting and obtaining the desired products in chemical reactions.