Exciting Chemistry Calculation: Propane Combustion!

How much carbon dioxide is produced upon the complete combustion of 29.4 L of propane?

Assume that the density of the liquid propane in the tank is 0.621 g/mL.

Answer:

61kg

Are you ready to dive into the world of chemistry and learn about the exciting process of propane combustion? Let's break it down step by step!

Calculating Carbon Dioxide Production from Propane Combustion

Like all hydrocarbons, propane combustion produces water and carbon dioxide. The balanced chemical equation for this reaction is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

First, we convert the given volume of propane (29.4 L) into grams using the density of the liquid propane (0.621 g/mL).

Mass = density * volume = 0.621 g/mL * 29,400 mL = 20,347.74 g

Next, we calculate the actual number of moles of propane produced, which is 462.44 moles.

Using the balanced equation, we find that 1 mole of propane produces 3 moles of carbon dioxide. Therefore, the actual moles of CO2 produced is 1387.35 moles.

Finally, the mass of carbon dioxide produced is calculated as 61,043 g. Converting this to kilograms, we get 61 kg.

So, upon the complete combustion of 29.4 L of propane, approximately 61 kg of carbon dioxide is produced. Isn't chemistry fascinating?