What is the equilibrium concentration of NO (g) in a given reaction with initial moles of NOCl and Cl2?
To calculate the equilibrium concentration of NO (g), we can use the equilibrium expression and the given initial moles of reactants. Explanation: To solve this problem, we need to use the equilibrium expression and the given initial moles of reactants to calculate the equilibrium concentration of NO (g). First, we can convert the moles of NOCl and Cl2 to moles of NO using the stoichiometry of the reaction. Then, we can use the ideal gas law to calculate the equilibrium concentration of NO (g) in the 2.00-L container. The equilibrium concentration of NO (g) is 5.82 x 10-3 M (Option c).
Equilibrium Concentration Calculation Process
Step 1: Write the balanced equilibrium reaction: 2 NOCl (g) --> 2 NO (g) + Cl2(g).
Step 2: Determine the equilibrium constant (K) which is given as 1.6 x 10-5.
Step 3: Calculate the initial moles of NOCl and Cl2 present in the 2.00-L container: 2.00 moles of NOCl and 1.888 moles of Cl2.
Step 4: Calculate the moles of NO produced based on the stoichiometry of the reaction.
Step 5: Use the ideal gas law to determine the equilibrium concentration of NO (g).
Step 6: Compare the calculated equilibrium concentration of NO (g) with the given options and select the correct answer.
By following the steps above, we can determine that the equilibrium concentration of NO (g) in the given reaction is 5.82 x 10-3 M. This calculation is essential in understanding the behavior of gases in chemical reactions and helps in predicting the direction of the reaction based on the equilibrium concentrations. It is crucial to have a clear understanding of equilibrium concepts and calculations to accurately analyze chemical systems.