Determining the Volume of Neon Gas Sample
What is the volume of a 3.50 mol Neon gas sample at 3.00 atm and 22.0°C?
The volume of a 3.50 mol Neon gas sample at 3.00 atm and 22.0°C is 82.59 liters.
Calculation Process
Gases follow the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin. To find the volume, we rearrange the formula: V = (nRT) / P.
Given Values
Number of moles (n): 3.50 mol
Pressure (P): 3.00 atm
Temperature (T): 22.0°C (convert to Kelvin by adding 273.15)
Gas constant (R): constant value
Volume Calculation
Substitute the values into the formula: V = (3.50 mol * R * 295.15 K) / 3.00 atm = 82.59 liters.
Significance
This volume represents the space occupied by the 3.50 mol of Neon gas at the given conditions of pressure and temperature. Understanding gas volume is crucial in various scientific and industrial applications.
Detailed Explanation
When dealing with gases, it's essential to utilize the ideal gas law to determine various properties like volume. In this case, by knowing the number of moles, pressure, and temperature of Neon gas, we were able to calculate its volume accurately. This calculation showcases the predictive power of the ideal gas law and its applicability in real-world scenarios.
For this specific Neon gas sample, the volume of 82.59 liters signifies the amount of space occupied by 3.50 moles of Neon gas. This understanding plays a crucial role in processes ranging from chemical reactions to environmental studies.
By grasping the fundamentals of gas behavior and the underlying principles of the ideal gas law, scientists and engineers can manipulate gases effectively for various purposes. Whether in laboratory experiments or industrial settings, accurate volume calculations are essential for achieving desired outcomes.