Chemistry Problem-Solving: Finding the Volume of Solution Needed
Exploring Chemistry Solution-Volume Calculation
When tackling chemistry problems involving finding the volume of solution needed, it's essential to remember the equation M1V1 = M2V2. This formula allows us to calculate the volume of a certain concentration solution needed to create a specific concentration solution.
In this scenario, we are given the following information:
M1 (initial molarity) = 4.70 M
V2 (final volume) = 0.480 L
M2 (final molarity) = 1.70 M
By plugging these values into the formula M1V1 = M2V2 and solving for V1, we can determine the volume of the 4.70 M solution of NaNO₃ needed:
(4.70 M)(V1) = (1.70 M)(0.480 L)
V1 = (1.70 M)(0.480 L) / (4.70 M) = 0.173 L
Therefore, the volume of the 4.70 M solution of NaNO₃ required to create a 0.480 L of 1.70 M solution is 0.173 L. This calculation demonstrates the power of understanding molarity and volume relationships in chemistry problem-solving.