Chemical Reaction: Calculating Dimethylglyoxime Solution Volume

How to calculate the volume of dimethylglyoxime solution needed for Reaction 7-2?

Given data: 0.998 4 g of steel with 2.07 wt% Ni and 2.15 wt% dimethylglyoxime solution with a density of 0.790 g/mL.

Answer:

The volume of solution required is 7.195 mL.

First, calculate the mass of Ni in the steel sample:

Mass of Ni = 0.9984 g x 2.07% = 0.0206 g

Next, determine the moles of Ni:

Moles of Ni = 0.0206 g / 58.7 g/mol = 0.0003509 mol

Calculate the moles of dimethylglyoxime needed:

Since 1 mole of Ni requires 2 moles of dimethylglyoxime, the moles needed for a 50% excess are 0.0010527 mol.

Find the mass of dimethylglyoxime:

Mass of dimethylglyoxime = 0.0010527 mol x 116.12 g/mol = 0.1222 g

Determine the weight of the solution:

0.1222 g of dimethylglyoxime corresponds to 5.684 g of the solution

Calculate the volume of the solution:

Density = 0.790 g/mL = 5.684 g / Volume

Therefore, Volume of solution = 7.195 mL

Final answer: Approximately 7.195 mL of a 2.15 wt% dimethylglyoxime solution should be used to provide a 50% excess for Reaction 7-2 with the given steel sample containing 2.07 wt% Ni.