Calculate the volume of phosphoric acid containing oxygen
How do we calculate the volume of phosphoric acid that contains 7.85 x 104 mg of oxygen?
What is the density of phosphoric acid and how do we convert the mass of oxygen from milligrams to grams?
Volume of Phosphoric Acid Containing Oxygen
To calculate the volume of phosphoric acid that contains 7.85 x 104 mg of oxygen, we need to first convert the mass of oxygen from milligrams to grams.
Given: Mass of Oxygen = 7.85 x 104 mg
The density of phosphoric acid is 1.88 g/cm3.
To convert the mass of oxygen from milligrams to grams, we use the conversion factor: 1 g = 1000 mg. Therefore, 7.85 x 104 mg of oxygen is equal to 78.5 g of oxygen.
Next, we need to calculate the mass of phosphoric acid containing 7.85 x 104 mg of oxygen. The molecular formula of phosphoric acid is H3PO4, which consists of 1 P atom, 4 O atoms, and 3 H atoms.
The molar mass of P is approximately 31 g/mol, O is approximately 16 g/mol, and H is approximately 1 g/mol. Therefore, the molar mass of H3PO4 is about 98 g/mol.
Since phosphoric acid contains 4 moles of oxygen atoms, the mass of oxygen in one mole of H3PO4 is 64 g.
Therefore, 78.5 g of oxygen is present in (78.5/64) * 98 = 120.39 g of phosphoric acid.
Using the density of phosphoric acid, we can calculate the volume in cm3 using the formula: Volume = Mass / Density.
Volume = 120.39 g / 1.88 g/cm3 = 64.03 cm3.