Calculate the Moles of Lead(II) Sulfide in Galena

How many moles of lead(II) sulfide are in 5.77 ft of galena x 10 moles?

Given data shows that 1579.5 moles of lead(II) sulfide are in 5.77 ft of galena x 10 moles. How can we calculate this?

Calculation of Moles of Lead(II) Sulfide in Galena

To calculate the moles of lead(II) sulfide in a given amount of galena, we can use the formula:

Moles = Mass / Molar mass

First, we convert the volume of galena from cubic feet to cubic centimeters:

5.77 ft = 5.77 * (30.48 cm/ft)^3 = 5057.24 cm³

Then, we calculate the mass of the galena using its density:

Mass = Density * Volume = 7.46 g/cm³ * 5057.24 cm³ = 37783.24 g

The molar mass of lead(II) sulfide (PbS) is the sum of the molar masses of lead (Pb) and sulfur (S):

Molar mass of PbS = 207.2 g/mol (Pb) + 32.07 g/mol (S) = 239.27 g/mol

Now, we can calculate the moles of lead(II) sulfide:

Moles = Mass / Molar mass = 37783.24 g / 239.27 g/mol ≈ 157.95 moles

Finally, we multiply by 10 moles to get the moles of lead(II) sulfide in 5.77 ft of galena x 10:

157.95 moles * 10 = 1579.5 moles

Calculating the moles of lead(II) sulfide in galena involves converting the volume to cubic centimeters, determining the mass based on density, calculating the molar mass of lead(II) sulfide, and finally applying the formula to find the moles. In this case, there are 1579.5 moles of lead(II) sulfide in 5.77 ft of galena multiplied by 10 moles.

This calculation showcases the importance of understanding the composition and properties of minerals like galena. By applying basic chemistry principles, we can determine the amount of specific components present in a given sample, allowing for further analysis and research.